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S triangle frog Stock Photos and Images
Solomon Islands eyelash frog (Ceratobatrachus guentheri) portrait, Solomon Islands. Stock Photohttps://www.alamy.com/licenses-and-pricing/?v=1https://www.alamy.com/solomon-islands-eyelash-frog-ceratobatrachus-guentheri-portrait-solomon-islands-image263022249.htmlRMW7WKFN–Solomon Islands eyelash frog (Ceratobatrachus guentheri) portrait, Solomon Islands.
. Railway maintenance engineering, with notes on construction . SB.Tan3. Method S-ine Method. Fig. 85.—Definition of Frog Number. the other hand, we find in Vol. 14, Bulletin 7 of the Interna-tional Railway Congress, July, 1900, the following: By a lin 8 crossing, most companies m ean a crossing whose legs formthe two equal sides of an isosceles triangle whose sides are eight times thelength of the base, and it appears that this is the simplest method ofdescription. (See Fig. 85jB.) * Manual, 1911, p. 85. OTHER TRACK MATERIAL 147 The first definition will give a frog angle of 7° 09 10 fora No. Stock Photohttps://www.alamy.com/licenses-and-pricing/?v=1https://www.alamy.com/railway-maintenance-engineering-with-notes-on-construction-sbtan3-method-s-ine-method-fig-85definition-of-frog-number-the-other-hand-we-find-in-vol-14-bulletin-7-of-the-interna-tional-railway-congress-july-1900-the-following-by-a-lin-8-crossing-most-companies-m-ean-a-crossing-whose-legs-formthe-two-equal-sides-of-an-isosceles-triangle-whose-sides-are-eight-times-thelength-of-the-base-and-it-appears-that-this-is-the-simplest-method-ofdescription-see-fig-85jb-manual-1911-p-85-other-track-material-147-the-first-definition-will-give-a-frog-angle-of-7-09-10-fora-no-image375800744.htmlRM2CRB5K4–. Railway maintenance engineering, with notes on construction . SB.Tan3. Method S-ine Method. Fig. 85.—Definition of Frog Number. the other hand, we find in Vol. 14, Bulletin 7 of the Interna-tional Railway Congress, July, 1900, the following: By a lin 8 crossing, most companies m ean a crossing whose legs formthe two equal sides of an isosceles triangle whose sides are eight times thelength of the base, and it appears that this is the simplest method ofdescription. (See Fig. 85jB.) * Manual, 1911, p. 85. OTHER TRACK MATERIAL 147 The first definition will give a frog angle of 7° 09 10 fora No.
Solomon Islands eyelash frog (Ceratobatrachus guentheri) on ground, Solomon Islands. Stock Photohttps://www.alamy.com/licenses-and-pricing/?v=1https://www.alamy.com/solomon-islands-eyelash-frog-ceratobatrachus-guentheri-on-ground-solomon-islands-image263022257.htmlRMW7WKG1–Solomon Islands eyelash frog (Ceratobatrachus guentheri) on ground, Solomon Islands.
![. Field-book for railroad engineers. Containing formulas for laying out curves, determining frog angles, levelling, calculating earth-work, etc., etc., together with tables of radii, ordinates deflections, long chords, magnetic variation, logarithms, logarithmic and natural sines, tangents, etc., etc . rossing, to find the chords A C and B C Solution. Draw E G perpendicular to the main track, and A LCM, and B D parallel to it. Denote theangle A E C by E. Then,since the angle A E L = AUG = S, we have CE L = E -- S,and in the right triangle CE jV (Tab. X. 2), CE cos. OEM =R cos. {E -]- S)=^ EM= Stock Photo](https://c8.alamy.com/comp/2CH11AR/field-book-for-railroad-engineers-containing-formulas-for-laying-out-curves-determining-frog-angles-levelling-calculating-earth-work-etc-etc-together-with-tables-of-radii-ordinates-deflections-long-chords-magnetic-variation-logarithms-logarithmic-and-natural-sines-tangents-etc-etc-rossing-to-find-the-chords-a-c-and-b-c-solution-draw-e-g-perpendicular-to-the-main-track-and-a-lcm-and-b-d-parallel-to-it-denote-theangle-a-e-c-by-e-thensince-the-angle-a-e-l-=-aug-=-s-we-have-ce-l-=-e-sand-in-the-right-triangle-ce-jv-tab-x-2-ce-cos-oem-=r-cos-e-s=-em=-2CH11AR.jpg ". Field-book for railroad engineers. Containing formulas for laying out curves, determining frog angles, levelling, calculating earth-work, etc., etc., together with tables of radii, ordinates deflections, long chords, magnetic variation, logarithms, logarithmic and natural sines, tangents, etc., etc . rossing, to find the chords A C and B C Solution. Draw E G perpendicular to the main track, and A LCM, and B D parallel to it. Denote theangle A E C by E. Then,since the angle A E L = AUG = S, we have CE L = E -- S,and in the right triangle CE jV (Tab. X. 2), CE cos. OEM =R cos. {E -]- S)=^ EM= Stock Photo")
. Field-book for railroad engineers. Containing formulas for laying out curves, determining frog angles, levelling, calculating earth-work, etc., etc., together with tables of radii, ordinates deflections, long chords, magnetic variation, logarithms, logarithmic and natural sines, tangents, etc., etc . rossing, to find the chords A C and B C Solution. Draw E G perpendicular to the main track, and A LCM, and B D parallel to it. Denote theangle A E C by E. Then,since the angle A E L = AUG = S, we have CE L = E -- S,and in the right triangle CE jV (Tab. X. 2), CE cos. OEM =R cos. {E -]- S)=^ EM= Stock Photohttps://www.alamy.com/licenses-and-pricing/?v=1https://www.alamy.com/field-book-for-railroad-engineers-containing-formulas-for-laying-out-curves-determining-frog-angles-levelling-calculating-earth-work-etc-etc-together-with-tables-of-radii-ordinates-deflections-long-chords-magnetic-variation-logarithms-logarithmic-and-natural-sines-tangents-etc-etc-rossing-to-find-the-chords-a-c-and-b-c-solution-draw-e-g-perpendicular-to-the-main-track-and-a-lcm-and-b-d-parallel-to-it-denote-theangle-a-e-c-by-e-thensince-the-angle-a-e-l-=-aug-=-s-we-have-ce-l-=-e-sand-in-the-right-triangle-ce-jv-tab-x-2-ce-cos-oem-=r-cos-e-s=-em=-image371889919.htmlRM2CH11AR–. Field-book for railroad engineers. Containing formulas for laying out curves, determining frog angles, levelling, calculating earth-work, etc., etc., together with tables of radii, ordinates deflections, long chords, magnetic variation, logarithms, logarithmic and natural sines, tangents, etc., etc . rossing, to find the chords A C and B C Solution. Draw E G perpendicular to the main track, and A LCM, and B D parallel to it. Denote theangle A E C by E. Then,since the angle A E L = AUG = S, we have CE L = E -- S,and in the right triangle CE jV (Tab. X. 2), CE cos. OEM =R cos. {E -]- S)=^ EM=
. American engineer and railroad journal . radius, the gauge and the frog angle being given, we mayproceed as follows : In fig. 4 let D B E = K F B znd K B = g. Then inthe right-angled triangle K F B the tangent FB-. (S) %Ti.KFB Now, in the right, angled triangle /J 5/=*there are giventhe three angles and the side F B, from which R jf t g = F B y. Cot. B A F. (6j l84 THE RAILROAD AND [April, l8g2> Example : Given the frog angle = 6° 21 34 and the gauge = 4ft. 8.J in. = 4.708 to find the radius = A, fig. 4. £■ = 4.708 0.6728365 A/=.ff = 6° 2134 Silt. 9.0444045 ^^.^=42.504 1.6284320 Thus, ha Stock Photohttps://www.alamy.com/licenses-and-pricing/?v=1https://www.alamy.com/american-engineer-and-railroad-journal-radius-the-gauge-and-the-frog-angle-being-given-we-mayproceed-as-follows-in-fig-4-let-d-b-e-=-k-f-b-znd-k-b-=-g-then-inthe-right-angled-triangle-k-f-b-the-tangent-fb-s-tikfb-now-in-the-right-angled-triangle-j-5=there-are-giventhe-three-angles-and-the-side-f-b-from-which-r-jf-t-g-=-f-b-y-cot-b-a-f-6j-l84-the-railroad-and-april-l8g2gt-example-given-the-frog-angle-=-6-21-34-and-the-gauge-=-4ft-8j-in-=-4708-to-find-the-radius-=-a-fig-4-=-4708-06728365-a=ff-=-6-2134-silt-90444045-=42504-16284320-thus-ha-image371999262.htmlRM2CH60RX–. American engineer and railroad journal . radius, the gauge and the frog angle being given, we mayproceed as follows : In fig. 4 let D B E = K F B znd K B = g. Then inthe right-angled triangle K F B the tangent FB-. (S) %Ti.KFB Now, in the right, angled triangle /J 5/=*there are giventhe three angles and the side F B, from which R jf t g = F B y. Cot. B A F. (6j l84 THE RAILROAD AND [April, l8g2> Example : Given the frog angle = 6° 21 34 and the gauge = 4ft. 8.J in. = 4.708 to find the radius = A, fig. 4. £■ = 4.708 0.6728365 A/=.ff = 6° 2134 Silt. 9.0444045 ^^.^=42.504 1.6284320 Thus, ha
. American engineer and railroad journal . Example No. 2 .• Given the radius of the main trackR = 573.69, the radius of the turnout curve, R = 380, thestandard gauge g— 5 ft. 6 in., and the narrow gauge the radius of the turnout = A, the standard gauge = g,and the narrow gauge = g. In the triangle/)-/ C there are given the side ^ C =. ? =: 3 ft. 6 in., to find the frog angle D .1 E = B A C,fig. 13 : ^ ^ (573.69 - 38o)+(573 69 - 2-75) + (380+2.75 - 3o) ^ j^, ^^2 s — (R — i g) = I 00 0.0000000 s - {R + ig — g) = 193 69.... 2.2848592 R+ i g — g — 379-^5 ar. comp.. 7.4210744 R — i g = 570 94- ar. Stock Photohttps://www.alamy.com/licenses-and-pricing/?v=1https://www.alamy.com/american-engineer-and-railroad-journal-example-no-2-given-the-radius-of-the-main-trackr-=-57369-the-radius-of-the-turnout-curve-r-=-380-thestandard-gauge-g-5-ft-6-in-and-the-narrow-gauge-the-radius-of-the-turnout-=-a-the-standard-gauge-=-gand-the-narrow-gauge-=-g-in-the-triangle-c-there-are-given-the-side-c-=-=-3-ft-6-in-to-find-the-frog-angle-d-1-e-=-b-a-cfig-13-57369-38o573-69-2-75-380275-3o-j-2-s-r-i-g-=-i-00-00000000-s-r-ig-g-=-193-69-22848592-r-i-g-g-379-5-ar-comp-74210744-r-i-g-=-570-94-ar-image371992093.htmlRM2CH5KKW–. American engineer and railroad journal . Example No. 2 .• Given the radius of the main trackR = 573.69, the radius of the turnout curve, R = 380, thestandard gauge g— 5 ft. 6 in., and the narrow gauge the radius of the turnout = A, the standard gauge = g,and the narrow gauge = g. In the triangle/)-/ C there are given the side ^ C =. ? =: 3 ft. 6 in., to find the frog angle D .1 E = B A C,fig. 13 : ^ ^ (573.69 - 38o)+(573 69 - 2-75) + (380+2.75 - 3o) ^ j^, ^^2 s — (R — i g) = I 00 0.0000000 s - {R + ig — g) = 193 69.... 2.2848592 R+ i g — g — 379-^5 ar. comp.. 7.4210744 R — i g = 570 94- ar.
![. American engineer and railroad journal . dius of the main track = A,the radius of the turnout — A, (he standard gauge = g,and the narrow gauge = g. In the triangle ./ /> C we have the side ./ C = A* + A^ — tr, the side A J> = A + i g, and the side li C =A? -/?. , . (/?-/?) + (A- + i^ - g) + (A- + ig)Let J = ^ « then, from trigonometry, we haveSin. i BAC :/i -(^ + ig-g)] [s-{/i + ig)] (A + i.g-i.-) C^+i.C) («4) metre = 3.281 ft.—to find the frog angle D A E = /? . / C,fig. 12 : (573 69-38o)4.(573-69+2-625—3-28i)+(38o4-2.625)s— ^ 574.674 s — {R-ykg-g) = ^Mo 02148438 s — (/?+ ii g) = 1 Stock Photo](https://c8.alamy.com/comp/2CH5KX7/american-engineer-and-railroad-journal-dius-of-the-main-track-=-athe-radius-of-the-turnout-a-he-standard-gauge-=-gand-the-narrow-gauge-=-g-in-the-triangle-gt-c-we-have-the-side-c-=-a-a-tr-the-side-a-jgt-=-a-i-g-and-the-side-li-c-=a-a-i-g-a-iglet-j-=-then-from-trigonometry-we-havesin-i-bac-i-ig-g-s-i-ig-a-ig-i-cic-4-metre-=-3281-ftto-find-the-frog-angle-d-a-e-=-cfig-12-573-69-38o4573-692-6253-28i38o4-2625s-574674-s-r-ykg-g-=-mo-02148438-s-ii-g-=-1-2CH5KX7.jpg ". American engineer and railroad journal . dius of the main track = A,the radius of the turnout — A, (he standard gauge = g,and the narrow gauge = g. In the triangle ./ /> C we have the side ./ C = A* + A^ — tr, the side A J> = A + i g, and the side li C =A? -/?. , . (/?-/?) + (A- + i^ - g) + (A- + ig)Let J = ^ « then, from trigonometry, we haveSin. i BAC :/i -(^ + ig-g)] [s-{/i + ig)] (A + i.g-i.-) C^+i.C) («4) metre = 3.281 ft.—to find the frog angle D A E = /? . / C,fig. 12 : (573 69-38o)4.(573-69+2-625—3-28i)+(38o4-2.625)s— ^ 574.674 s — {R-ykg-g) = ^Mo 02148438 s — (/?+ ii g) = 1 Stock Photo")
. American engineer and railroad journal . dius of the main track = A,the radius of the turnout — A, (he standard gauge = g,and the narrow gauge = g. In the triangle ./ /> C we have the side ./ C = A* + A^ — tr, the side A J> = A + i g, and the side li C =A? -/?. , . (/?-/?) + (A- + i^ - g) + (A- + ig)Let J = ^ « then, from trigonometry, we haveSin. i BAC :/i -(^ + ig-g)] [s-{/i + ig)] (A + i.g-i.-) C^+i.C) («4) metre = 3.281 ft.—to find the frog angle D A E = /? . / C,fig. 12 : (573 69-38o)4.(573-69+2-625—3-28i)+(38o4-2.625)s— ^ 574.674 s — {R-ykg-g) = ^Mo 02148438 s — (/?+ ii g) = 1 Stock Photohttps://www.alamy.com/licenses-and-pricing/?v=1https://www.alamy.com/american-engineer-and-railroad-journal-dius-of-the-main-track-=-athe-radius-of-the-turnout-a-he-standard-gauge-=-gand-the-narrow-gauge-=-g-in-the-triangle-gt-c-we-have-the-side-c-=-a-a-tr-the-side-a-jgt-=-a-i-g-and-the-side-li-c-=a-a-i-g-a-iglet-j-=-then-from-trigonometry-we-havesin-i-bac-i-ig-g-s-i-ig-a-ig-i-cic-4-metre-=-3281-ftto-find-the-frog-angle-d-a-e-=-cfig-12-573-69-38o4573-692-6253-28i38o4-2625s-574674-s-r-ykg-g-=-mo-02148438-s-ii-g-=-1-image371992271.htmlRM2CH5KX7–. American engineer and railroad journal . dius of the main track = A,the radius of the turnout — A, (he standard gauge = g,and the narrow gauge = g. In the triangle ./ /> C we have the side ./ C = A* + A^ — tr, the side A J> = A + i g, and the side li C =A? -/?. , . (/?-/?) + (A- + i^ - g) + (A- + ig)Let J = ^ « then, from trigonometry, we haveSin. i BAC :/i -(^ + ig-g)] [s-{/i + ig)] (A + i.g-i.-) C^+i.C) («4) metre = 3.281 ft.—to find the frog angle D A E = /? . / C,fig. 12 : (573 69-38o)4.(573-69+2-625—3-28i)+(38o4-2.625)s— ^ 574.674 s — {R-ykg-g) = ^Mo 02148438 s — (/?+ ii g) = 1
. American engineer and railroad journal . Example No. i .• Given the radius of the main trackA = 573 69, the radius ot the turnout A^ = 380. the stand-ard gauge ;, = 4 ft. 8A in. = 4.708. the narrow gauge j, =3 ft. o in.—to find the frog angle D A E = B A C, fig. 12 : (573-69-3So) +(573-69 +2-354-3-ooo) + (3So + 2-354) .,, ,,,J— —574-544 Here in the triangle A /> Cv/e have the side A C = Ri ■, the side A B = R + ig — •/, and the side /> CR - R. As before, let s = Ihe i sum of the three sides, or (R - R) + {R - ig) + jR + ig -g). s — {R + i ^ — g) = 1 .Soo 0.1760913 s — (R + i g) = 192. Stock Photohttps://www.alamy.com/licenses-and-pricing/?v=1https://www.alamy.com/american-engineer-and-railroad-journal-example-no-i-given-the-radius-of-the-main-tracka-=-573-69-the-radius-ot-the-turnout-a-=-380-the-stand-ard-gauge-=-4-ft-8a-in-=-4708-the-narrow-gauge-j-=3-ft-o-into-find-the-frog-angle-d-a-e-=-b-a-c-fig-12-573-69-3so-573-69-2-354-3-ooo-3so-2-354-j-574-544-here-in-the-triangle-a-gt-cve-have-the-side-a-c-=-ri-the-side-a-b-=-r-ig-and-the-side-gt-cr-r-as-before-let-s-=-ihe-i-sum-of-the-three-sides-or-r-r-r-ig-jr-ig-g-s-r-i-g-=-1-soo-01760913-s-r-i-g-=-192-image371992102.htmlRM2CH5KM6–. American engineer and railroad journal . Example No. i .• Given the radius of the main trackA = 573 69, the radius ot the turnout A^ = 380. the stand-ard gauge ;, = 4 ft. 8A in. = 4.708. the narrow gauge j, =3 ft. o in.—to find the frog angle D A E = B A C, fig. 12 : (573-69-3So) +(573-69 +2-354-3-ooo) + (3So + 2-354) .,, ,,,J— —574-544 Here in the triangle A /> Cv/e have the side A C = Ri ■, the side A B = R + ig — •/, and the side /> CR - R. As before, let s = Ihe i sum of the three sides, or (R - R) + {R - ig) + jR + ig -g). s — {R + i ^ — g) = 1 .Soo 0.1760913 s — (R + i g) = 192.
. Elements of railroad track and construction . ch and B 6 is 6J inches, B 6 is 6 inches, and the angleh AiB =Uk B =s; and in the triangle &A B. sm s AB = ^ = 2S («1> from which Table XV may be computed. TABLE XV.Switch-rails and Angles. Length of Switch-rail, S. Frog. No. Actual Theoretical Switch Angle, s. Feet. Feet. 4 11.0 11.46 2° 36 19 5 11.0 11.46 2 36 19 6 11.0 11.46 2 36 19 7 16.5 17.19 1 44 11 8 16.5 17.19 1 44 11 9 16.5 17.19 1 44 11 10 16.5 17.19 1 44 11 12 22.0 22.92 1 18 08 16 33.0 34.38 0 52 05 18 33.0 34.38 0 52 05 20 33.0 34.38 0 52 05 24 33.0 34.38 0 52 05 129. The Practic Stock Photohttps://www.alamy.com/licenses-and-pricing/?v=1https://www.alamy.com/elements-of-railroad-track-and-construction-ch-and-b-6-is-6j-inches-b-6-is-6-inches-and-the-angleh-aib-=uk-b-=s-and-in-the-triangle-a-b-sm-s-ab-=-=-2s-1gt-from-which-table-xv-may-be-computed-table-xvswitch-rails-and-angles-length-of-switch-rail-s-frog-no-actual-theoretical-switch-angle-s-feet-feet-4-110-1146-2-36-19-5-110-1146-2-36-19-6-110-1146-2-36-19-7-165-1719-1-44-11-8-165-1719-1-44-11-9-165-1719-1-44-11-10-165-1719-1-44-11-12-220-2292-1-18-08-16-330-3438-0-52-05-18-330-3438-0-52-05-20-330-3438-0-52-05-24-330-3438-0-52-05-129-the-practic-image375609349.htmlRM2CR2DFH–. Elements of railroad track and construction . ch and B 6 is 6J inches, B 6 is 6 inches, and the angleh AiB =Uk B =s; and in the triangle &A B. sm s AB = ^ = 2S («1> from which Table XV may be computed. TABLE XV.Switch-rails and Angles. Length of Switch-rail, S. Frog. No. Actual Theoretical Switch Angle, s. Feet. Feet. 4 11.0 11.46 2° 36 19 5 11.0 11.46 2 36 19 6 11.0 11.46 2 36 19 7 16.5 17.19 1 44 11 8 16.5 17.19 1 44 11 9 16.5 17.19 1 44 11 10 16.5 17.19 1 44 11 12 22.0 22.92 1 18 08 16 33.0 34.38 0 52 05 18 33.0 34.38 0 52 05 20 33.0 34.38 0 52 05 24 33.0 34.38 0 52 05 129. The Practic
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